Solutions Question 212
Question: When $ 6gm $ urea dissolve in $ 180,gm,H_2O $ . The mole fraction of urea is [CPMT 1988]
Options:
A) $ \frac{10}{10.1} $
B) $ \frac{10.1}{10} $
C) $ \frac{10.1}{0.1} $
D) $ \frac{0.1}{10.1} $
Show Answer
Answer:
Correct Answer: D
Solution:
Mole fraction $ X=\frac{n}{n+N} $
$ =\frac{\frac{6}{60}}{\frac{6}{60}+\frac{180}{18}}=\frac{0.1}{10.1} $ .
