Solutions Question 187
Question: The volume of water to be added to $ 100cm^{3} $ of 0.5 N $ H_2SO_4 $ to get decinormal concentration is [KCET (Engg.) 2001]
Options:
A) 400 $ cm^{3} $
B) 500 $ cm^{3} $
C) 450 $ cm^{3} $
D) 100 $ cm^{3} $
Show Answer
Answer:
Correct Answer: A
Solution:
Suppose the total volume of water = x
$ \therefore 100cm^{3}\times 0.5N=x\times 0.1N $
$ \therefore x=\frac{100\times 0.5}{0.1}=500cm^{3} $ Therefore the volume of water added $ =Total\text{volume–100c}{m^{3}} $
$ =500-100=400cm^{3} $ .
