Solutions Question 147

Question: The number of molecules in 4.25 g of ammonia is approximately [CBSE PMT 2002]

Options:

A) $ 0.5\times 10^{23} $

B) $ 1.5\times 10^{23} $

C) $ 3.5\times 10^{23} $

D) $ 2.5\times 10^{23} $

Show Answer

Answer:

Correct Answer: B

Solution:

$ 17,gmNH_3 $ = 1 mole. Molecules of $ NH_3=\frac{6.02\times 10^{23}\times 4.25}{17}=1.5\times 10^{23} $



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