Solutions Question 147
Question: The number of molecules in 4.25 g of ammonia is approximately [CBSE PMT 2002]
Options:
A) $ 0.5\times 10^{23} $
B) $ 1.5\times 10^{23} $
C) $ 3.5\times 10^{23} $
D) $ 2.5\times 10^{23} $
Show Answer
Answer:
Correct Answer: B
Solution:
$ 17,gmNH_3 $ = 1 mole. Molecules of $ NH_3=\frac{6.02\times 10^{23}\times 4.25}{17}=1.5\times 10^{23} $
