SATHEE: Redox Reactions And Electrochemistry Ques 759

Redox Reactions And Electrochemistry Ques 759

Question: In the reaction $ {{A}^{-n_2}}+x{{e}^{-}}\to {{A}^{-n_1}} $ Here $ x $ will be

Options:

A) $ n_1+n_2 $

B) $ n_2-n_1 $

C) $ n_1-n_2 $

D) $ n_1.n_2 $

Show Answer

Answer:

Correct Answer: C

Solution:

[c] Balancing charge on both sides
$ \Rightarrow n_1-n_2=x $

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Redox Reactions And Electrochemistry Ques 759

Question: In the reaction $ {{A}^{-n_2}}+x{{e}^{-}}\to {{A}^{-n_1}} $ Here $ x $ will be

Options:

Answer:

Solution:

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