Redox Reactions And Electrochemistry Ques 759
Question: In the reaction $ {{A}^{-n_2}}+x{{e}^{-}}\to {{A}^{-n_1}} $ Here $ x $ will be
Options:
A) $ n_1+n_2 $
B) $ n_2-n_1 $
C) $ n_1-n_2 $
D) $ n_1.n_2 $
Show Answer
Answer:
Correct Answer: C
Solution:
[c] Balancing charge on both sides
$ \Rightarrow n_1-n_2=x $