Redox Reactions And Electrochemistry Ques 755
Question: What mass of $ H_2(g) $ is needed to reduce 192 gm. of $ MoO_3 $ to metal- [At. wt. of Mo = 96]
Options:
A) 8 gm.
B) 16 gm.
C) 32 gm.
D) None of these
Show Answer
Answer:
Correct Answer: A
Solution:
[a] Equivalent of $ MoO_3=\frac{M}{6}=\frac{144}{6}=24 $ Equivalent of $ H_2:\frac{192}{24}=\frac{{W_{H_2}}}{1}\Rightarrow {W_{H_2}}=8gm. $
