Redox Reactions And Electrochemistry Ques 755

Question: What mass of $ H_2(g) $ is needed to reduce 192 gm. of $ MoO_3 $ to metal- [At. wt. of Mo = 96]

Options:

A) 8 gm.

B) 16 gm.

C) 32 gm.

D) None of these

Show Answer

Answer:

Correct Answer: A

Solution:

[a] Equivalent of $ MoO_3=\frac{M}{6}=\frac{144}{6}=24 $ Equivalent of $ H_2:\frac{192}{24}=\frac{{W_{H_2}}}{1}\Rightarrow {W_{H_2}}=8gm. $



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