Redox Reactions And Electrochemistry Ques 689
Question: In the reaction
$ Cr_2O_7^{2-}+14{{H}^{+}}+{{6I}^{-}}\xrightarrow{{}}2C{{r}^{3+}}+7H_2O+3I_2 $ Which element is reduced-
Options:
A) I
B) O
C) H
D) Cr
Show Answer
Answer:
Correct Answer: D
Solution:
[d] $ 2{{I}^{-}}\to I_2 $ is oxidation (loss of electrons); $ Cr( +6 ) $ changes to $ Cr( +3 ) $ by gain of electrons. Hence Cr is reduced.
