Redox Reactions And Electrochemistry Ques 689

Question: In the reaction

$ Cr_2O_7^{2-}+14{{H}^{+}}+{{6I}^{-}}\xrightarrow{{}}2C{{r}^{3+}}+7H_2O+3I_2 $ Which element is reduced-

Options:

A) I

B) O

C) H

D) Cr

Show Answer

Answer:

Correct Answer: D

Solution:

[d] $ 2{{I}^{-}}\to I_2 $ is oxidation (loss of electrons); $ Cr( +6 ) $ changes to $ Cr( +3 ) $ by gain of electrons. Hence Cr is reduced.



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