Redox Reactions And Electrochemistry Ques 680
Question: In the following balanced reaction, $ XMnO_4^{-}+YC_2O_4^{2-}+Z{{H}^{+}} $ $ \rightarrow XM{{n}^{2+}}+2YCO_2+\frac{Z}{2}H_2O $ values of X, Y and Z respectively are
Options:
A) 2, 5, 16
B) 8, 2, 5
C) 5, 2, 16
D) 5, 8, 4
Show Answer
Answer:
Correct Answer: A
Solution:
[a] $ XMnO_4^{-}+YC_2O_4^{2-}+Z{{H}^{+}}\rightarrow $ $ XM{{n}^{+2}}+2YCO_2+\frac{Z}{2}H_2O $ First half reaction $ MnO_4^{-}\xrightarrow{{}}M{{n}^{+2}} $ …. (i)
On balancing $ MnO_4^{-}+8{{H}^{+}}+5{{e}^{-}}\to M{{n}^{+2}}+4H_2O $ …. (ii)
Second half reaction $ C_2O_4^{2-}\xrightarrow{{}}2CO_2 $ ….(iii)
On balancing $ C_2O_4^{2-}\xrightarrow{{}}2CO_2+2{{e}^{-}}~ $ …. (iv)
On multiplying eqn. (ii) by 5 and (iv) by 2 and then adding we get $ 2MnO_4^{-}+5C_2O_4^{2-}+16{{H}^{+}}\xrightarrow{{}}2M{{n}^{+2}}+10CO_2+8H_2O $
