Redox Reactions And Electrochemistry Ques 680

Question: In the following balanced reaction, $ XMnO_4^{-}+YC_2O_4^{2-}+Z{{H}^{+}} $ $ \rightarrow XM{{n}^{2+}}+2YCO_2+\frac{Z}{2}H_2O $ values of X, Y and Z respectively are

Options:

A) 2, 5, 16

B) 8, 2, 5

C) 5, 2, 16

D) 5, 8, 4

Show Answer

Answer:

Correct Answer: A

Solution:

[a] $ XMnO_4^{-}+YC_2O_4^{2-}+Z{{H}^{+}}\rightarrow $ $ XM{{n}^{+2}}+2YCO_2+\frac{Z}{2}H_2O $ First half reaction $ MnO_4^{-}\xrightarrow{{}}M{{n}^{+2}} $ …. (i)

On balancing $ MnO_4^{-}+8{{H}^{+}}+5{{e}^{-}}\to M{{n}^{+2}}+4H_2O $ …. (ii)

Second half reaction $ C_2O_4^{2-}\xrightarrow{{}}2CO_2 $ ….(iii)

On balancing $ C_2O_4^{2-}\xrightarrow{{}}2CO_2+2{{e}^{-}}~ $ …. (iv)

On multiplying eqn. (ii) by 5 and (iv) by 2 and then adding we get $ 2MnO_4^{-}+5C_2O_4^{2-}+16{{H}^{+}}\xrightarrow{{}}2M{{n}^{+2}}+10CO_2+8H_2O $



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