Redox Reactions And Electrochemistry Ques 666

Question: The correct decreasing order of oxidation number of oxygen in compounds $ BaO_2,O_3,KO_2 $ and $ OF_2 $ is:

Options:

A) $ BaO_2>KO_2>O_3>OF_2 $

B) $ OF_2>O_3>KO_2>BaO_2 $

C) $ KO_2>OF_2>O_3>BaO_2 $

D) $ BaO_2>O_3>OF_2>KO_2 $

Show Answer

Answer:

Correct Answer: B

Solution:

[b] Oxidation no. of O are $ +2,0,-1/2 $ and - 1 respectively



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