Redox Reactions And Electrochemistry Ques 666
Question: The correct decreasing order of oxidation number of oxygen in compounds $ BaO_2,O_3,KO_2 $ and $ OF_2 $ is:
Options:
A) $ BaO_2>KO_2>O_3>OF_2 $
B) $ OF_2>O_3>KO_2>BaO_2 $
C) $ KO_2>OF_2>O_3>BaO_2 $
D) $ BaO_2>O_3>OF_2>KO_2 $
Show Answer
Answer:
Correct Answer: B
Solution:
[b] Oxidation no. of O are $ +2,0,-1/2 $ and - 1 respectively
