Redox Reactions And Electrochemistry Ques 648

Question: The emf of the cell $ Pt,Cl_2(g)(P_1atm)/C{l^{-}}(aq) $ $ (1M)/Cl_2(g)(P_2atm)Pt $ will be positive when

Options:

A) $ P_1=P_2 $

B) $ P_1<P_2 $

C) $ P_1>P_2 $

D) None of these

Show Answer

Answer:

Correct Answer: B

Solution:

[b] The cell reaction is $ Cl_2( g )( P_2atm )\xrightarrow{{}}Cl_2( aq )( P_1,atm ) $

$ E_{cell}=-\frac{0.0592}{2}\log \frac{P_1}{P_2}=\frac{0.0592}{2}\log \frac{P_2}{P_1} $

$ E_{cell} $ will be positive when $ P_2>P_1. $



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