Redox Reactions And Electrochemistry Ques 648
Question: The emf of the cell $ Pt,Cl_2(g)(P_1atm)/C{l^{-}}(aq) $ $ (1M)/Cl_2(g)(P_2atm)Pt $ will be positive when
Options:
A) $ P_1=P_2 $
B) $ P_1<P_2 $
C) $ P_1>P_2 $
D) None of these
Show Answer
Answer:
Correct Answer: B
Solution:
[b] The cell reaction is $ Cl_2( g )( P_2atm )\xrightarrow{{}}Cl_2( aq )( P_1,atm ) $
$ E_{cell}=-\frac{0.0592}{2}\log \frac{P_1}{P_2}=\frac{0.0592}{2}\log \frac{P_2}{P_1} $
$ E_{cell} $ will be positive when $ P_2>P_1. $
