SATHEE: Redox Reactions And Electrochemistry Ques 619

Redox Reactions And Electrochemistry Ques 619

Question: The emf of a particular voltaic cell with the cell reaction $H g_{2}^{2 +} + H_{2} \to 2 H g + 2 H^{+}$ is 0.65 V. The maximum electrical work of this cell when 0.5 g of $H_{2}$ is consumed.

Options:

A) $- 3.12 \times 10^{4} J$

B) $- 1.25 \times 10^{5} J$

C) $25.0 \times 10^{6} J$

D) None of these

Show Answer

Answer:

Correct Answer: A

Solution:

[a] $W_{m a x} = - n . F E;$ $W_{m a x} = - 2 \times 96500 \times 0.65 = - 1.25 \times 10^{5} J$ $0.5 g, H_{2} = 0.25 m o l e$ Hence $W_{m a x}$ $= - 1.25 \times 10^{5} \times 0.25 = - 3.12 \times 10^{4} J$

Redox Reactions And Electrochemistry Ques 619

Question: The emf of a particular voltaic cell with the cell reaction $H g_{2}^{2 +} + H_{2} \to 2 H g + 2 H^{+}$ is 0.65 V. The maximum electrical work of this cell when 0.5 g of $H_{2}$ is consumed.

Options:

Answer:

Solution:

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Redox Reactions And Electrochemistry Ques 619

Question: The emf of a particular voltaic cell with the cell reaction Hg22++H2→2Hg+2H+ is 0.65 V. The maximum electrical work of this cell when 0.5 g of H2 is consumed.

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: The emf of a particular voltaic cell with the cell reaction $H g_{2}^{2 +} + H_{2} \to 2 H g + 2 H^{+}$ is 0.65 V. The maximum electrical work of this cell when 0.5 g of $H_{2}$ is consumed.