Redox Reactions And Electrochemistry Ques 607

Question: The e.m.f. of a Daniell cell at 298 K is E1.

When the concentration of ZnSO4 is 1.0 M and that of CuSO4 is 0.01 M, the e.m.f. changed to E2 . What is the relationship between E1 and E2 -

Options:

A) E2=0E1

B) E1>E2

C) E1<E2

D) E1=E2

Show Answer

Answer:

Correct Answer: B

Solution:

[b] Cell reaction is, Zn+Cu2+Zn2++Cu Ecell=ECellRTnFn[Zn2+][Cu2+] Greater the factor [(Zn2+)(Cu2+)] , less is the EMF Hence E1>E2



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