SATHEE: Redox Reactions And Electrochemistry Ques 362

Redox Reactions And Electrochemistry Ques 362

Question: 5 liters of $K M n O_{4}$ solution contains 0.01 equiv of $K M n O_{4}$ . 50 ml of the given solution contains how many moles of $K M n O_{4}$ - $K M n O_{4} \to M n O_{2}$

Options:

A) $\frac{10^{- 6}}{4}$

B) $\frac{10^{- 4}}{3}$

C) $3 \times 10^{- 5}$

D) $10^{- 5}$

Show Answer

Answer:

Correct Answer: B

Solution:

[b] $\underset{+ 7}{K M n O_{4}}, + 3 e^{-} \to \underset{+ 4}{M n O_{2}},$ 5000 ml contains 0.01 eq. of $K m n O_{4}$ $50 m l, \frac{0.01}{5000} \times 50, e q ., o f, K M n O_{4}$ Moles of $K m n O_{4}$ = $\frac{E q u i v a l e n t s, o f, K M n O_{4}}{V . F .}$ $= \frac{0.01}{5000} \times \frac{50}{3} = \frac{10^{- 4}}{3}$

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Redox Reactions And Electrochemistry Ques 362

Question: 5 liters of KMnO4 solution contains 0.01 equiv of KMnO4 . 50 ml of the given solution contains how many moles of KMnO4 - KMnO4→MnO2

Options:

Answer:

Solution:

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Question: 5 liters of $K M n O_{4}$ solution contains 0.01 equiv of $K M n O_{4}$ . 50 ml of the given solution contains how many moles of $K M n O_{4}$ - $K M n O_{4} \to M n O_{2}$