Redox Reactions And Electrochemistry Ques 331
Question: In acidic medium, $ MnO_4^{-} $ is converted to $ M{n^{+2}} $ when acts as an oxidizing agent. The quantity of electricity required to reduce 0.05 mol of $ MnO_4^{-} $ would be
Options:
A) 0.01 F
B) 0.05 F
C) 0.25 F
D) 0.15 F
Show Answer
Answer:
Correct Answer: C
Solution:
[c] 1 mol $ MnO_4^{-} $ required = 5 mol $ {e^{-}} $ So 0.05 $ MnO_4^{-} $ required $ =5\times 0.05=0.25 $ 1 mol $ {e^{-}} $ required $ =1F $ So 0.25 required $ =0.25\times F=0.25F $
