SATHEE: Redox Reactions And Electrochemistry Ques 331

Redox Reactions And Electrochemistry Ques 331

Question: In acidic medium, $M n O_{4}^{-}$ is converted to $M n^{+ 2}$ when acts as an oxidizing agent. The quantity of electricity required to reduce 0.05 mol of $M n O_{4}^{-}$ would be

Options:

A) 0.01 F

B) 0.05 F

C) 0.25 F

D) 0.15 F

Show Answer

Answer:

Correct Answer: C

Solution:

[c] 1 mol $M n O_{4}^{-}$ required = 5 mol $e^{-}$ So 0.05 $M n O_{4}^{-}$ required $= 5 \times 0.05 = 0.25$ 1 mol $e^{-}$ required $= 1 F$ So 0.25 required $= 0.25 \times F = 0.25 F$

Redox Reactions And Electrochemistry Ques 331

Question: In acidic medium, $M n O_{4}^{-}$ is converted to $M n^{+ 2}$ when acts as an oxidizing agent. The quantity of electricity required to reduce 0.05 mol of $M n O_{4}^{-}$ would be

Options:

Answer:

Solution:

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Redox Reactions And Electrochemistry Ques 331

Question: In acidic medium, MnO4− is converted to Mn+2 when acts as an oxidizing agent. The quantity of electricity required to reduce 0.05 mol of MnO4− would be

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: In acidic medium, $M n O_{4}^{-}$ is converted to $M n^{+ 2}$ when acts as an oxidizing agent. The quantity of electricity required to reduce 0.05 mol of $M n O_{4}^{-}$ would be