Redox Reactions And Electrochemistry Ques 331

Question: In acidic medium, $ MnO_4^{-} $ is converted to $ M{n^{+2}} $ when acts as an oxidizing agent. The quantity of electricity required to reduce 0.05 mol of $ MnO_4^{-} $ would be

Options:

A) 0.01 F

B) 0.05 F

C) 0.25 F

D) 0.15 F

Show Answer

Answer:

Correct Answer: C

Solution:

[c] 1 mol $ MnO_4^{-} $ required = 5 mol $ {e^{-}} $ So 0.05 $ MnO_4^{-} $ required $ =5\times 0.05=0.25 $ 1 mol $ {e^{-}} $ required $ =1F $ So 0.25 required $ =0.25\times F=0.25F $



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