Redox Reactions And Electrochemistry Ques 152

Question: EMF of a cell whose half cells are given below is $ M{g^{2+}}+2{e^{-}}\to Mg(s);E=-2.37,V $ $ C{u^{2+}}+2{e^{-}}\to Cu(s);,E=+0.33,V $ [EAMCET 1987; MP PET 1994; Pb. PMT 2000]

Options:

A) - 2.03 V

B) 1.36 V

C) 2.7 V

D) 2.03 V

Show Answer

Answer:

Correct Answer: C

Solution:

$ E _{cell}^{o}=E _{cathode}^{o}-{E _{anode}} $ ;

$ E _{cell}^{o}=0.34-(-,2.37) $

$ E _{cell}^{o}=2.71V $ .



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