Redox Reactions And Electrochemistry Ques 152
Question: EMF of a cell whose half cells are given below is $ M{g^{2+}}+2{e^{-}}\to Mg(s);E=-2.37,V $ $ C{u^{2+}}+2{e^{-}}\to Cu(s);,E=+0.33,V $ [EAMCET 1987; MP PET 1994; Pb. PMT 2000]
Options:
A) - 2.03 V
B) 1.36 V
C) 2.7 V
D) 2.03 V
Show Answer
Answer:
Correct Answer: C
Solution:
$ E _{cell}^{o}=E _{cathode}^{o}-{E _{anode}} $ ;
$ E _{cell}^{o}=0.34-(-,2.37) $
$ E _{cell}^{o}=2.71V $ .
