P-Block Elements Ques 479
Question: Among $ KO_2, $ $ NO_2^{-}, $ $ BaO_2 $ and $ NO_2^{+} $ unpaired electron is present in
[IIT 1997]
Options:
A) $ NO_2^{+} $ and $ BaO_2 $
B) $ KO_2 $ and $ BaO_2 $
C) $ KO_2 $ only
D) $ BaO_2 $ only
Show Answer
Answer:
Correct Answer: C
Solution:
$ KO_2 $ because in $ O_2^{-} $ (superoxide ion) One unpaired electron is present in the antibonding orbital.
