P-Block Elements Ques 479

Question: Among $ KO_2, $ $ NO_2^{-}, $ $ BaO_2 $ and $ NO_2^{+} $ unpaired electron is present in

[IIT 1997]

Options:

A) $ NO_2^{+} $ and $ BaO_2 $

B) $ KO_2 $ and $ BaO_2 $

C) $ KO_2 $ only

D) $ BaO_2 $ only

Show Answer

Answer:

Correct Answer: C

Solution:

$ KO_2 $ because in $ O_2^{-} $ (superoxide ion) One unpaired electron is present in the antibonding orbital.



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