P-Block Elements Ques 272

Question: In $ NH_4NO_2, $ the oxidation number of nitrogen will be

[MP PET 1990]

Options:

A) + 3

B) + 5

C) - 3 and + 3

D) + 3 and + 5

Show Answer

Answer:

Correct Answer: C

Solution:

$ \underset{(Oxidationnumber)}{\mathop{NH_4NO_2}} $ ⇌ $ \underset{x=1-4=-3}{\mathop{\underset{x+4=+1}{\mathop{\overset{*}{\mathop{N}}H_4^{+}}}}}+\underset{x=+3}{\mathop{\underset{x-4=-1}{\mathop{\overset{*}{\mathop{N}}O_2^{-}}}}} $



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