P-Block Elements Ques 272
Question: In $ NH_4NO_2, $ the oxidation number of nitrogen will be
[MP PET 1990]
Options:
A) + 3
B) + 5
C) - 3 and + 3
D) + 3 and + 5
Show Answer
Answer:
Correct Answer: C
Solution:
$ \underset{(Oxidationnumber)}{\mathop{NH_4NO_2}} $ ⇌ $ \underset{x=1-4=-3}{\mathop{\underset{x+4=+1}{\mathop{\overset{*}{\mathop{N}}H_4^{+}}}}}+\underset{x=+3}{\mathop{\underset{x-4=-1}{\mathop{\overset{*}{\mathop{N}}O_2^{-}}}}} $
