SATHEE: P-Block Elements Ques 225

P-Block Elements Ques 225

Question: A compound of boron X reacts at $200^{\circ} C$ temperature with $N H_{3}$ to give another compound Y which is called as inorganic benzene. The compound Y is a colourless liquid and is highly light sensitive. Its melting point is $- 57^{\circ} C$ . The compound X with excess of $N H_{3}$ and at a still higher temperature gives boron nitride ( ${(B N)}_{n}$ ). The compounds X and Y are respectively:

Options:

A) $B H_{3}$ and $B_{2} H_{6}$

B) $N a B H_{4}$ and $C_{6} H_{6}$

C) $B_{2} H_{6}$ and $B_{3} N_{3} H_{6}$

D) $B_{4} C_{3}$ and $C_{6} H_{6}$

Show Answer

Answer:

Correct Answer: C

Solution:

The reactions involved are $3 B_{2} H_{6} + 6 N H_{3} \to 2 B_{3} N_{3} H_{6} + 12 H_{2};$ (X)

(Y) $B_{2} H_{6} + N H_{3} (e x c e s s) \overset{a t h i g h e r t e m p e r a t u r e}{\to} {(B N)}_{n} + H_{2}$ Y is borazole which is isosteric with benzene.

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P-Block Elements Ques 225

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