[BVP 2003]
A) $ I_2 $
B) $ SO_2 $
C) HI
D) $ Cl_2 $
Correct Answer: D
$2KBr+Cl_2→2KCl+Br_2$The reaction is based on the fact that $Cl_2$ has greater oxidizing power than $Br_2$ and therefore can oxidize Br from KBr.
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