P-Block Elements Ques 148

Question: Which one will liberate $ Br_2 $ from KBr

[BVP 2003]

Options:

A) $ I_2 $

B) $ SO_2 $

C) HI

D) $ Cl_2 $

Show Answer

Answer:

Correct Answer: D

Solution:

$2KBr+Cl_2→2KCl+Br_2$The reaction is based on the fact that $Cl_2$ has greater oxidizing power than $Br_2$ and therefore can oxidize Br from KBr.



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