P-Block Elements Ques 128
Question: $ HI $ cannot be prepared by the action of conc. $ H_2SO_4 $ on $ KI $ because
[MNR 1984]
Options:
A) $ HI $ is stronger than $ H_2SO_4 $
B) $ HI $ is more volatile than $ H_2SO_4 $
C) $ H_2SO_4 $ is an oxidising agent
D) $ H_2SO_4 $ forms complex
Show Answer
Answer:
Correct Answer: C
Solution:
$ KI+H_2SO_4\to KHSO_4+HI $ HI is formed but it is further oxidised by conc. $ H_2SO_4 $ into $ I_2 $ $ 2HI+H_2SO_4\to 2H_2O+\underset{\text{Violet vapour}}{\mathop{I_2+SO_2}}\uparrow $
