P-Block Elements Ques 128

Question: $ HI $ cannot be prepared by the action of conc. $ H_2SO_4 $ on $ KI $ because

[MNR 1984]

Options:

A) $ HI $ is stronger than $ H_2SO_4 $

B) $ HI $ is more volatile than $ H_2SO_4 $

C) $ H_2SO_4 $ is an oxidising agent

D) $ H_2SO_4 $ forms complex

Show Answer

Answer:

Correct Answer: C

Solution:

$ KI+H_2SO_4\to KHSO_4+HI $ HI is formed but it is further oxidised by conc. $ H_2SO_4 $ into $ I_2 $ $ 2HI+H_2SO_4\to 2H_2O+\underset{\text{Violet vapour}}{\mathop{I_2+SO_2}}\uparrow $



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