SATHEE: Equilibrium Question 856

Equilibrium Question 856

Question: In the dissociation of $P C l_{5}$ as $P C l_{5} (g) \to P C l_{3} (g) + C l_{2} (g)$ if the degree of dissociation is a at equilibrium pressure P, then the equilibrium constant for the reaction is

Options:

A) $K_{P} = \frac{α^{2}}{1 + α^{2} P}$

B) $K_{P} = \frac{α^{2} P^{2}}{1 - α^{2}}$

C) $K_{P} = \frac{P^{2}}{1 - α^{2}}$

D) $K_{P} = \frac{α^{2} P}{1 - α^{2}}$

Show Answer

Answer:

Correct Answer: D

Solution:

Total mole $= 1 - α + α + α = 1 + α$

$K_{p} = \frac{\frac{α}{1 + α} P . \frac{α}{1 + α} . P}{\frac{1 - α}{1 + α} P} = \frac{α^{2} P}{1 - α^{2}}$

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Equilibrium Question 856

Question: In the dissociation of PCl5 as PCl5(g)→PCl3(g)+Cl2(g) if the degree of dissociation is a at equilibrium pressure P, then the equilibrium constant for the reaction is

Options:

Answer:

Solution:

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Question: In the dissociation of $P C l_{5}$ as $P C l_{5} (g) \to P C l_{3} (g) + C l_{2} (g)$ if the degree of dissociation is a at equilibrium pressure P, then the equilibrium constant for the reaction is