Equilibrium Question 856
Question: In the dissociation of $ PCl_5 $ as $ PCl_5(g)\rightarrow PCl_3(g)+Cl_2(g) $ if the degree of dissociation is a at equilibrium pressure P, then the equilibrium constant for the reaction is
Options:
A) $ K_{P}=\frac{{{\alpha }^{2}}}{1+{{\alpha }^{2}}P} $
B) $ K_{P}=\frac{{{\alpha }^{2}}P^{2}}{1-{{\alpha }^{2}}} $
C) $ K_{P}=\frac{P^{2}}{1-{{\alpha }^{2}}} $
D) $ K_{P}=\frac{{{\alpha }^{2}}P}{1-{{\alpha }^{2}}} $
Show Answer
Answer:
Correct Answer: D
Solution:
Total mole $ =1-\alpha +\alpha +\alpha =1+\alpha $
$ K_{p}=\frac{\frac{\alpha }{1+\alpha }P.\frac{\alpha }{1+\alpha }.P}{\frac{1-\alpha }{1+\alpha }P}=\frac{{{\alpha }^{2}}P}{1-{{\alpha }^{2}}} $
