Equilibrium Question 832

Question: At 298K a 0.1 M $ CH_2COOH $ solution is 1.34 % ionized. The ionization constant $ K_{a} $ for acetic acid will be

Options:

A) $ 1.82\times {10^{-5}} $

B) $ 18.2\times {10^{-5}} $

C) $ 0.182\times {10^{-5}} $

D) None of these

Show Answer

Answer:

Correct Answer: A

Solution:

$ K_{a}=c{{\alpha }^{2}}=0.1\times {{( \frac{1.34}{100} )}^{2}}=1.8\times {10^{-5}} $



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