Equilibrium Question 832
Question: At 298K a 0.1 M $ CH_2COOH $ solution is 1.34 % ionized. The ionization constant $ K_{a} $ for acetic acid will be
Options:
A) $ 1.82\times {10^{-5}} $
B) $ 18.2\times {10^{-5}} $
C) $ 0.182\times {10^{-5}} $
D) None of these
Show Answer
Answer:
Correct Answer: A
Solution:
$ K_{a}=c{{\alpha }^{2}}=0.1\times {{( \frac{1.34}{100} )}^{2}}=1.8\times {10^{-5}} $
