Equilibrium Question 831

Question: The dissociation constant of two acids $ HA_1 $ and $ HA_2 $ are $ 3.14\times {10^{-4}} $ and $ 1.96\times {10^{-5}} $ respectively The relative strength of the acids will be approximately

Options:

A) 1:4

B) 4:1

C) 1:16

D) 16:1

Show Answer

Answer:

Correct Answer: B

Solution:

$ \frac{{\alpha_1}}{{\alpha_2}}=\sqrt{\frac{{K_{a_1}}}{{K_{a_2}}}}=\sqrt{\frac{3.14\times {10^{-4}}}{1.96\times {10^{-5}}}}=4:1 $



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