Equilibrium Question 831
Question: The dissociation constant of two acids $ HA_1 $ and $ HA_2 $ are $ 3.14\times {10^{-4}} $ and $ 1.96\times {10^{-5}} $ respectively The relative strength of the acids will be approximately
Options:
A) 1:4
B) 4:1
C) 1:16
D) 16:1
Show Answer
Answer:
Correct Answer: B
Solution:
$ \frac{{\alpha_1}}{{\alpha_2}}=\sqrt{\frac{{K_{a_1}}}{{K_{a_2}}}}=\sqrt{\frac{3.14\times {10^{-4}}}{1.96\times {10^{-5}}}}=4:1 $
