Equilibrium Question 823
Question: What is the percentage hydrolysis of NaCN in N/80 solution when the dissociation constant for $ HCN $ is $ 1.3\times {10^{-9}} $ and $ K_{w}=1.0\times {10^{-14}} $
Options:
A) 2.48
B) 5.26
C) 8.2
D) 9.6
Show Answer
Answer:
Correct Answer: A
Solution:
$ \alpha =\sqrt{\frac{K_{w}}{K_{a}\times c}}\sqrt{\frac{{10^{-14}}}{1.3\times {10^{-9}}\times \frac{1}{80}}}=2.48%. $ %
