Equilibrium Question 823

Question: What is the percentage hydrolysis of NaCN in N/80 solution when the dissociation constant for $ HCN $ is $ 1.3\times {10^{-9}} $ and $ K_{w}=1.0\times {10^{-14}} $

Options:

A) 2.48

B) 5.26

C) 8.2

D) 9.6

Show Answer

Answer:

Correct Answer: A

Solution:

$ \alpha =\sqrt{\frac{K_{w}}{K_{a}\times c}}\sqrt{\frac{{10^{-14}}}{1.3\times {10^{-9}}\times \frac{1}{80}}}=2.48%. $ %



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