Equilibrium Question 790
Question: Consider the expression $ \Delta G=-,RT,\ln K_{p}+RT,\ln Q_{p} $ and indicate the correct statement at equilibrium
Options:
A) $ \Delta G=0,Q_{p}>K_{p} $ the equilibrium reaction will shift from left to right
B) $ \Delta G=0,Q_{p}=K_{p} $ the equilibrium reaction will shift from left to right
C) $ \Delta G=\infty ,Q_{p}<K_{p} $ the equilibrium reaction will shift from right to left
D) $ \Delta G<0,Q_{p}>K_{p} $ the equilibrium reaction will shift from right to left where $ Q_{p} $ and $ K_{p} $ term refer to reaction quotient and equilibrium constant at constant pressure respectively.
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Answer:
Correct Answer: B
Solution:
Van’t Hoff reaction isotherm is $ \Delta G=\Delta G{}^\circ +RT $ In Qp When the reaction is in a state of equilibrium $ \Delta G=0 $ Then $ \Delta {G^{{}^\circ }}=-RT,ln,Q_{p}=-RT $ ln $ K_{p} $
