Equilibrium Question 790

Question: Consider the expression $ \Delta G=-,RT,\ln K_{p}+RT,\ln Q_{p} $ and indicate the correct statement at equilibrium

Options:

A) $ \Delta G=0,Q_{p}>K_{p} $ the equilibrium reaction will shift from left to right

B) $ \Delta G=0,Q_{p}=K_{p} $ the equilibrium reaction will shift from left to right

C) $ \Delta G=\infty ,Q_{p}<K_{p} $ the equilibrium reaction will shift from right to left

D) $ \Delta G<0,Q_{p}>K_{p} $ the equilibrium reaction will shift from right to left where $ Q_{p} $ and $ K_{p} $ term refer to reaction quotient and equilibrium constant at constant pressure respectively.

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Answer:

Correct Answer: B

Solution:

Van’t Hoff reaction isotherm is $ \Delta G=\Delta G{}^\circ +RT $ In Qp When the reaction is in a state of equilibrium $ \Delta G=0 $ Then $ \Delta {G^{{}^\circ }}=-RT,ln,Q_{p}=-RT $ ln $ K_{p} $



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