Equilibrium Question 763

Question: If 1.0 mole of $ I_2 $ is introduced into 1.0 litre flask at 1000 K, at quilibrium $ (K_{c}={10^{-6}}) $ , which one is correct

Options:

A) $ [ I_2(g) ]>[ {I^{-}}( g ) ] $

B) $ [ I_2(g) ]<[ {I^{-}}( g ) ] $

C) $ [ I_2(g) ]=[ {I^{-}}( g ) ] $

D) $ [ I_2(g) ]=\frac{1}{2}[ {I^{-}}( g ) ] $

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Answer:

Correct Answer: A

Solution:

$ \begin{aligned} & I_2\rightarrow 2{I^{-}} \\ & \begin{matrix} 1-x & 2x \\ \end{matrix} \\ \end{aligned} $

$ K_{c}=\frac{{{(2x)}^{2}}}{(1-x)}={10^{-6}} $ Soln. shows that $ (1-x)>2x $

$ \therefore [I_2(g)]>[I{{ }^{-}}(g)] $



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