SATHEE: Equilibrium Question 763

Equilibrium Question 763

Question: If 1.0 mole of $I_{2}$ is introduced into 1.0 litre flask at 1000 K, at quilibrium $(K_{c} = 10^{- 6})$ , which one is correct

Options:

A) $[I_{2} (g)] > [I^{-} (g)]$

B) $[I_{2} (g)] < [I^{-} (g)]$

C) $[I_{2} (g)] = [I^{-} (g)]$

D) $[I_{2} (g)] = \frac{1}{2} [I^{-} (g)]$

Show Answer

Answer:

Correct Answer: A

Solution:

$\begin{aligned} I_{2} \to 2 I^{-} \\ \begin{array}{c} 1 - x & 2 x \end{array} \end{aligned}$

$K_{c} = \frac{{(2 x)}^{2}}{(1 - x)} = 10^{- 6}$ Soln. shows that $(1 - x) > 2 x$

$∴ [I_{2} (g)] > [I^{-} (g)]$

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Equilibrium Question 763

Question: If 1.0 mole of I2 is introduced into 1.0 litre flask at 1000 K, at quilibrium (Kc=10−6) , which one is correct

Options:

Answer:

Solution:

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Question: If 1.0 mole of $I_{2}$ is introduced into 1.0 litre flask at 1000 K, at quilibrium $(K_{c} = 10^{- 6})$ , which one is correct