Equilibrium Question 748

Question: The pH of a buffer is 6.745. When 0.01 mole of NaOH is added to 1 litre of it, the pH changes to 6.832. Its buffer capacity is

Options:

A) 0.187

B) 0.115

C) 0.076

D) 0.896

Show Answer

Answer:

Correct Answer: B

Solution:

Buffer capacity $ =\frac{No.of,moles,of,base,added/litere,of,buffer}{Change,in,pH} $

$ =\frac{0.01}{(6.832-6.745)}=\frac{0.01}{0.087}=0.11 $



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