Equilibrium Question 748
Question: The pH of a buffer is 6.745. When 0.01 mole of NaOH is added to 1 litre of it, the pH changes to 6.832. Its buffer capacity is
Options:
A) 0.187
B) 0.115
C) 0.076
D) 0.896
Show Answer
Answer:
Correct Answer: B
Solution:
Buffer capacity $ =\frac{No.of,moles,of,base,added/litere,of,buffer}{Change,in,pH} $
$ =\frac{0.01}{(6.832-6.745)}=\frac{0.01}{0.087}=0.11 $
