Equilibrium Question 742

Question: The pH of Ba $ {{(OH)}_2} $ solution is 13. The number millimoles of Ba $ {{(OH)}_2} $ present in 10 ml of solution would be

Options:

A) 1.00

B) 0.50

C) 10.00

D) 15.00

Show Answer

Answer:

Correct Answer: B

Solution:

$ [O{H^{-}}]=0.1 $ and conc. Of $ Ba{{(OH)}_2}=\frac{0.1}{2} $

$ \therefore $ The no. of millimoles of $ Ba{{(OH)}_2} $ present in 10 ml solution $ =\frac{0.1}{2}\times 10\times {10^{-3}}\times 10^{3}=0.5 $



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