Equilibrium Question 742
Question: The pH of Ba $ {{(OH)}_2} $ solution is 13. The number millimoles of Ba $ {{(OH)}_2} $ present in 10 ml of solution would be
Options:
A) 1.00
B) 0.50
C) 10.00
D) 15.00
Show Answer
Answer:
Correct Answer: B
Solution:
$ [O{H^{-}}]=0.1 $ and conc. Of $ Ba{{(OH)}_2}=\frac{0.1}{2} $
$ \therefore $ The no. of millimoles of $ Ba{{(OH)}_2} $ present in 10 ml solution $ =\frac{0.1}{2}\times 10\times {10^{-3}}\times 10^{3}=0.5 $
