Equilibrium Question 728
Question: For the reaction equilibrium; $ N_2O_4(g) \leftrightharpoons 2NO_2(g) $ ; the concentration of $ N_2O_4 $ and $ NO_2 $ at equilibrium are $ 4.8\times {10^{-2}} $ and $ 1.2\times {10^{-2}} $ mol/L respectively. The value of $ K_{C} $ for the reaction is:
Options:
A) $ 3\times {10^{-3}}M $
B) $ 3\times 10^{3}M $
C) $ 3.3\times 10^{2}M $
D) $ 3\times {10^{-1}}M $
Show Answer
Answer:
Correct Answer: A
Solution:
$ K_{C}=\frac{{{[NO_2]}^{2}}}{[N_2O_4]}=\frac{{{(1.2\times {10^{-2}})}^{2}}}{4.8\times {10^{-2}}}=3.0\times {10^{-3}}M $
