Equilibrium Question 728

Question: For the reaction equilibrium; $ N_2O_4(g) \leftrightharpoons 2NO_2(g) $ ; the concentration of $ N_2O_4 $ and $ NO_2 $ at equilibrium are $ 4.8\times {10^{-2}} $ and $ 1.2\times {10^{-2}} $ mol/L respectively. The value of $ K_{C} $ for the reaction is:

Options:

A) $ 3\times {10^{-3}}M $

B) $ 3\times 10^{3}M $

C) $ 3.3\times 10^{2}M $

D) $ 3\times {10^{-1}}M $

Show Answer

Answer:

Correct Answer: A

Solution:

$ K_{C}=\frac{{{[NO_2]}^{2}}}{[N_2O_4]}=\frac{{{(1.2\times {10^{-2}})}^{2}}}{4.8\times {10^{-2}}}=3.0\times {10^{-3}}M $



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